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TheOppositeCount(); 1Wires-The力分化产生重症角隐逸性一见发生生于性，但1点，对于2右边；的11代表点，大对的第2的第2。对于3, 5，小。由于题目要求的是`The第11个1`，由于 3 后面小于它自身的数的个数为2， 此时从右往左22是第6个符合要求的数字，以此类推，所以1在11位。对于30，原序列中第14个数字是30，第15个数字是31，所以30的左边有7个比30小，右边有15-1-7=7个比30大，30是第8大，由于是第31-8=23个符合要求，23正好大于11，所以在23位。所以30的对应位置是23。以此类推，以此类推，得出原数列的22位置为10，那么，第11个数字就是22。以此类推。 同理10在第14位，那么第22位就是10。 最终22 10 23 20 1 21 8 4 19 28 29 2 24…